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0=1600-16t^2
We move all terms to the left:
0-(1600-16t^2)=0
We add all the numbers together, and all the variables
-(1600-16t^2)=0
We get rid of parentheses
16t^2-1600=0
a = 16; b = 0; c = -1600;
Δ = b2-4ac
Δ = 02-4·16·(-1600)
Δ = 102400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{102400}=320$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-320}{2*16}=\frac{-320}{32} =-10 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+320}{2*16}=\frac{320}{32} =10 $
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